cos arc csc (1241/280)
=cos arc sin (280/1241)
=cos arc cos √[1-(280/1241)²]
=1209/1241
设 x = arccsc(1241/280),则 cscx = 1241/280,
cosx = [ √( 1241^2 - 280^2 ) ]/1241= 1209/1241;
故 cos[ arccsc(1241/280) ] = cosx = 1209/1241 。
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